Melody

Why are you talking like I wrote that last annonymous comment Chris?

I did not write that.    

However,

I just looked at the question and I agree with you and anon.  That is how I would have done it.

I am not saying it is necessarily correct but it does make sense to me.     

P(no more thatn 4 fours) = P(no fours)+P(1four)+P(2 fours)+P(3 fours)+P(4 fours)

$$\\\left(\frac{5}{6}\right)^{12}
\;\;+\;\;^{12}C_1\left(\frac{1}{6}\right)^{1}\left(\frac{5}{6}\right)^{11}
\;\;+\;\;^{12}C_2 \left(\frac{1}{6}\right)^{2}\left(\frac{5}{6}\right)^{10}\\\\
\;\;+\;\;^{12}C_3\left(\frac{1}{6}\right)^{3}\left(\frac{5}{6}\right)^{9}
\;\;+\;\;^{12}C_4\left(\frac{1}{6}\right)^{4}\left(\frac{5}{6}\right)^{8}$$

Look in the sticky notes on the right of this page.  ☺

Good answer but don't forget the units.  In this case metres.  :)

look here

Thank you for all your help Rosala.   Did you remember to bring the chocolates and the flowers ?

Alan's birthday is the 21st which is today for me but it is still tomorrow for you and for him. 

@@ End of Day Wrap    Fri 20/2/15     Sydney, Australia   Time 12:05 am   (Really Sat morning.)   ♪ ♫

Today our great answers were delivered by Geno3141, Sasini, CPhill, Hellokittygirl156, Rosala, gliu1, Alan, Badinage, InovativeProgrammer and Sorasyn.  A big thank you to each of you. 

I answered very few questions today.  I am away from home for a few days.  Sorry.  Most questions were answered but there are planty left for answerers to find if they look just a little.

Sat 21/2/15

I have added this calc to our reference material stick note.  

Hit the [2nd]  button.

inverse sine is asin