Melody

Hi 315 :)

Let K be the average number of Kilometres per year

Let C be the yearly compensation

The first one,

C1 = 0.223K+2000

when k=18000    C1= 0.223*18000+200 = 4214

The second one, 

C2 = 0.32K

When K=18000  C2=0.32*18000 = 5760

So at 18,000 km per year the second one gives the better compensation

The reimbursements will be the same when  C1=C2

0.223K+2000=0.32K

             2000= (0.32-0.223)K

2000/(0.32-0.223) = 20618.5567010309278350515463917525773195876288659793814432989691

the reimburements will be the same if the annual distance travelled is  20619 km

Here is the graph :)

sketch the triangle.

Remember that the longest side is opposite the biggest angle and vise verse.

Use the cosine rule

3-3*6+2

=3 - 18 +2

=  -13

0+1-1+1-1+1-1+1-1x0

=0  +1-1    +1-1   +1-1   +1-1x0

=0  +0    +0  +0   +1-0

=1

Sorry, I am not sure how to do part b - I am still considering . ://

I may answer it later.

Hi Why

I am on my phone do layout is difficult.

P of no lefts = 0.92^20

P ( at most 2 lefts )

=P ( no  lefts )+P ( 1 lefts )+P ( 2 lefts )

=20C0×0.92^20+20C1×0.08×0.92^19+20C2×0.08^2×0.92^18

Etc

Mean=20×0.08

SD=sqrt( 20×0.08×0.92  )

I suggest you make sure the web2.0 calc is set to degrees and then type in tan(260) and then press equals.

I don't think that the brackets are needed either.

What's 4 x y + 34 - 2 ?

4xy + 34 - 2 = 4xy + 32

1/(8x)-2/(3x)+5/(6x)=3&1/2 Whats x?

\(\frac{1}{8x}-\frac{2}{3x}+\frac{5}{6x}=3\frac{1}{2}\\ \frac{1}{8x}-\frac{2}{3x}+\frac{5}{6x}=\frac{7}{2}\\~\\ \mbox{The lowest common denominator is 24x}\\~\\ 24x\times(\frac{1}{8x}-\frac{2}{3x}+\frac{5}{6x})=24x\times(\frac{7}{2})\\ (\frac{24x}{8x}-\frac{2*24x}{3x}+\frac{5*24x}{6x})=(\frac{7*24x}{2})\\ 3-16+20=84x\\ 7=84x\\ \frac{7}{84}=x\\ x=\frac{1}{12}\\\)

find Secant of 11pi/4

11pi/4=3pi/4 second quad    

\(sec\frac{11\pi}{4}\\=sec\frac{3\pi}{4}\\=1\div cos\frac{3\pi}{4}\\ =1\div -cos(\pi-\frac{3\pi}{4})\\ =1\div -cos(\frac{\pi}{4})\\ =1\div (\frac{-1}{\sqrt2})\\ =-\sqrt2\)