Attn: grmolives,
Here is the last time that you asked this question.
https://web2.0calc.com/questions/help-with-algebra_2
You are expected to interact with the original answerer, on the original thread.
Please do not just ignore the answer you are given and repost.
That is rude.
Any new answer should go on the ORIGINAL post. Thank you.
Thanks guest, I'll take another look.
2^n*3^(2n) - 1
\(2^n*3^{2n} - 1=18^n-1 \)
| n | 2 | 3 | 4 | 5 | 6 |
| f(n) | 323 | 5831 | 104975 | ||
| factor(f(n)) | 17* 19 | 17*7^3 | 17* ... |
ok, your answer could well be correct, it certainly works for the first 3 terms,
This is not a proof that it will always be so. Do you know how to prove it?