Melody

Ok thanks for your explanation.

I still do not even understand the question, 

But it doesn't matter.

Why?

I do not know if you are supposed to do this with calculus or with physics formulas.

I usually use calculus

If you say up is positive direction then

acceleration = gravity = -9.8m/s^2

Initial speed is 0

initial height is h

After 2.25 secs the father falls h metres and is at a height of 0.

\(\ddot{x}=-9.8m/s^2\\ \dot{x}=-9.8t\;m/sec\\ x=\frac{-9.8t^2}{2}+h\;metres\\ when\;\;t=2.25\;\;x=0\\ 0=\frac{-9.8*2.25^2}{2}+h\\ 0=-24.80625+h\\ h=24.80625 metres.\)

If the feather was in a room full of air then I think it would drop a lot more slowly because of the air resistence.

I am not good at Physics but that sounds right to me.

When you say oxygen, I assume you really mean all gasses.

So the feather is falling in a vacuum and the bowling bowl is falling where there is air resistance.

I think the ball would fall more slowly.

What is the question ?

I got 1

\(\text{Let u, v be distinct complex numbers. }\\ If\;\;u^2=v\;\;and\;\;v^2=u, \;\; what \;\;is \;\;uv\\ \)

\(uv=Ae^{\alpha i }*Be^{\beta i}\\ uv=ABe^{(\alpha +\beta) i}\\\)

Let

\(u=Ae^{\alpha i}\qquad \qquad v=Be^{\beta i}\\ u^2=A^2e^{2\alpha i}\qquad \quad v^2=B^2e^{2\beta i}\\~\\ u=v^2 \qquad \qquad \qquad v=u^2 \\ Ae^{\alpha i}=B^2e^{2\beta i}\quad \quad Be^{\beta i}=A^2e^{2\alpha i}\\~\\ Ae^{\alpha i}Be^{\beta i}=B^2e^{2\beta i}(A^2e^{2\alpha i})\\ ABe^{\alpha i+\beta i}=A^2B^2e^{2\alpha i+2\beta i}\\ e^{\alpha i+\beta i - ( 2\alpha i+2\beta i) }=AB\\ AB=e^{-i(\alpha +\beta ) }\\ \)

so

\(uv=ABe^{(\alpha +\beta) i}\\ uv=e^{-(\alpha+\beta)i}*e^{(\alpha +\beta) i}\\ uv=e^0\\ uv=1\)

Coding:

\text{Let u, v be distinct complex numbers. }\\
If\;\;u^2=v\;\;and\;\;v^2=u, \;\; what \;\;is \;\;uv\\

uv=Ae^{\alpha i }*Be^{\beta i}\\
 

u=Ae^{\alpha i}\qquad \qquad v=Be^{\beta i}\\
u^2=A^2e^{2\alpha i}\qquad \quad v^2=B^2e^{2\beta i}\\~\\
u=v^2 \qquad \qquad           \qquad          v=u^2                      \\
Ae^{\alpha i}=B^2e^{2\beta i}\quad \quad                  Be^{\beta i}=A^2e^{2\alpha i}\\~\\

Ae^{\alpha i}Be^{\beta i}=B^2e^{2\beta i}(A^2e^{2\alpha i})\\
ABe^{\alpha i+\beta i}=A^2B^2e^{2\alpha i+2\beta i}\\
e^{\alpha i+\beta i   - (  2\alpha i+2\beta i) }=AB\\
AB=e^{-i(\alpha +\beta ) }\\

uv=ABe^{(\alpha +\beta) i}\\
uv=e^{-(\alpha+\beta)i}*e^{(\alpha +\beta) i}\\
uv=e^0\\
uv=1

This does not make sense to me.

You have not actually given us the question.