Attn: WoidSmiley69
It is time for you to start presenting your questions properly.
I would be interested in looking at this one if it was not presented so poorly.
It is really good to see you all collaborating together :)
The length is 3 times longer
so the area is 3^2 more
and the volume is 3^3 more
3^3=27
Volume of B is 25.12*27 = 678.24 cu feet
Yes, it had only just been posted. So why didn't you wait?
\(\left( \frac{(2a^{-3}b^4)^2}{(3a^5b)^{-2}} \right)^{-1}\\ = \frac{(3a^5b)^{-2}} {(2a^{-3}b^4)^2} \\ = \frac{1} {(2a^{-3}b^4)^2 (3a^5b)^{2}} \\ = \frac{1} {(4a^{-6}b^8) (9a^{10}b^2)} \\ = \frac{1} {36a^{4}b^{10}} \\\)
Which is the same as EP's answer :)
Use cosine rule.
If you do not know what that is then google it.
It is a rectangle.
You must know some of those answers.
Which ones do you know?
Maybe you need to be more specific with what is causing you problems........
Drop perpendiculars from A and another from B to meet the tangent line.
Now you have 2 similar right angled triangles
Let x=length BC
Now use ratios in similar triangles to solve for x
Where did the image go? Was it blocked by the original site because the student was cheating?
\(\frac{k!}{k}=\frac{1*2*3*\dots (k-2)*(k-1)*k}{k}=1*2*3*\dots (k-2)*(k-1)=(k-1)!\)
+118727 
