Please don't answer over me when I have given a teaching answer.
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I do not think that it is usually best for people to be given full answers.
This should not be just a cheat site.
Draw a triangle.
Dawsen city aiport is at one vertice
in 2 hours how far does each plane fly? Those distances are on the two sides radiating from Dawson city
The other side is 1500km
Use cosine rule to find the angle.
p = 2q
q=2r so p=4r
p+r = 5 so 4r+r=5 so 5r=5 so r=1
so
q=2
p=4
That is assuming I kept the ones I took from you .
But I didn't keep them. I gave them to the needy of Sherwood Forest because I am Robin Hood..
In disguise, obviously.
There are only two possible areas for the intersection of all 4 circles. ( assuming that is what the question means.)
0 or pi units squared.
Maybe this is not what the question means. What is the area between the 4 circles???? Really I do not know what area is being referred to.
Well, I do not know how many I have but you have 85.
I guess I have as many as I started out with.
2x+5y=-8
multiply by 3
6x+15y=-24 (1)
6x=16+a-15y
6x+15y = 16+a (2)
These will be the same line and therefore have infinite simultaneous solutions if
16+a = -24
a= -40
Thanks EP
Tr1ck if you still have questions or concerns please keep asking .
We like interacting with people here
Thanks catmg
Hi Tr1
Think about this
3x + 5x = 8x because you started with 3x and you added another 5x. so you have (3+5)x
ctmeg had
z^4(z^3 + 8) - 2i(z^3 + 8) = 0
Here you have z^4 lots of (x^3+8) and from that you are taking away 2i lots of (z^3+8)
so you end up with
\((z^4-2i) \;\;lots\;\; of \;\;(z^3+8) = (z^4-2i) ( z^3+8) \)
Think about it.
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+118705 
