radio

8x+12>7x+2

x+12>2

x>2-12

x>-2

$${\frac{{\mathtt{a}}}{{\mathtt{5}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{15}} = {\mathtt{\,-\,}}{\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{2}}}}$$

$${\frac{{\mathtt{a}}}{{\mathtt{5}}}} = {\mathtt{\,-\,}}{\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{2}}}}{\mathtt{\,-\,}}{\mathtt{15}}$$

$${\mathtt{a}} = {\mathtt{5}}{\mathtt{\,\times\,}}\left({\mathtt{\,-\,}}{\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{2}}}}{\mathtt{\,-\,}}{\mathtt{15}}\right)$$

$${\mathtt{a}} = {\mathtt{5}}{\mathtt{\,\times\,}}\left({\mathtt{\,-\,}}{\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{2}}}}{\mathtt{\,-\,}}{\mathtt{15}}\right) \Rightarrow {\mathtt{a}} = -{\mathtt{87.5}}$$

Or if on the right side was-(3+1/2)

$${\frac{{\mathtt{a}}}{{\mathtt{5}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{15}} = {\mathtt{\,-\,}}\left({\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right)$$

$${\mathtt{a}} = {\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{\,-\,}}\left({\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{15}}$$

$${\mathtt{a}} = {\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{\,-\,}}\left({\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{15}} \Rightarrow {\mathtt{a}} = -{\mathtt{2.5}}$$

$${\mathtt{\,-\,}}{\mathtt{6.8}}{\mathtt{\,-\,}}{\frac{{\mathtt{x}}}{{\mathtt{1.2}}}} = -{\mathtt{2.9}}$$

$${\mathtt{\,-\,}}{\mathtt{6.8}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2.9}} = {\frac{{\mathtt{x}}}{{\mathtt{1.2}}}}$$

$${\mathtt{1.2}}{\mathtt{\,\times\,}}\left({\mathtt{\,-\,}}{\mathtt{6.8}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2.9}}\right) = {\mathtt{x}}$$

$${\mathtt{1.2}}{\mathtt{\,\times\,}}\left({\mathtt{\,-\,}}{\mathtt{6.8}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2.9}}\right) = {\mathtt{x}} \Rightarrow {\mathtt{x}} = {\mathtt{\,-\,}}{\frac{{\mathtt{117}}}{{\mathtt{25}}}} \Rightarrow {\mathtt{x}} = -{\mathtt{4.68}}$$

$${\frac{{\mathtt{1}}}{{\mathtt{81}}}} = {\mathtt{0.012\: \!345\: \!679\: \!012\: \!345\: \!7}}$$

Oh ok. I see.

This pattern works with $${\frac{{\mathtt{1}}}{{{\mathtt{99}}}^{{\mathtt{2}}}}}$$ which gives all the 2 digit numbers - 1 of them.

-2/5,-0.2,0.2.

-2/5 is -0.4.

10^2 = 100 is the one i was thinking of but 2 - (1+1)=000 also works

No. pi is 3.14159562559, not 3.4

Pi is an irrational number which is roughly 22/7.

It is used in numerous mathematical equations about circles, $${\mathtt{\pi}}$$d is used to find the circumference of a circle, pi multiplied by the diameter. To find the area of a circle, used $${\mathtt{\pi}}$$r^2. Pi times the radius squared.

The circumference equation can be rearranged to find pi. $${\mathtt{\pi}} = {\frac{{\mathtt{C}}}{{\mathtt{d}}}}$$ where C is the circumference and d is the diameter.

So angle FED is $${\mathtt{180}}{\mathtt{\,-\,}}{\mathtt{45}}{\mathtt{\,-\,}}{\mathtt{63}} = {\mathtt{72}}$$

The Sine rules states that sinD/d = sinE/e = sinF/f, where the lowercase letter is the side opposite to the angle in captials.

sinE/3.8=sinF/DE

$${\frac{\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}{\left({\mathtt{72}}^\circ\right)}}{{\mathtt{3.8}}}} = {\mathtt{0.250\: \!278\: \!030\: \!603\: \!947\: \!4}}$$

$${\frac{\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}{\left({\mathtt{72}}^\circ\right)}}{{\mathtt{3.8}}}} = {\frac{\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}{\left({\mathtt{45}}^\circ\right)}}{{\mathtt{x}}}}$$

$${\mathtt{x}} = {\frac{\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}{\left({\mathtt{45}}^\circ\right)}}{{\mathtt{0.250\: \!278\: \!030\: \!603\: \!947\: \!4}}}} \Rightarrow {\mathtt{x}} = {\mathtt{2.825\: \!285\: \!061\: \!899\: \!665\: \!9}}$$

Round this to the nearest tenth of an inch and that would be 2.8 inches.

So the question is -3-(-6)+5^4=628

$${\left(\left({\mathtt{\,-\,}}{\mathtt{3}}{\mathtt{\,\small\textbf+\,}}\left({\mathtt{6}}\right)\right){\mathtt{\,\small\textbf+\,}}{\mathtt{5}}\right)}^{{\mathtt{4}}} = {\mathtt{4\,096}}$$

the -(-6) was changed to a +6 because 2 minuses = a positive