Rom

\(a=4~m/s^2\\~\\ s_0 = 0\\ s(t) = \dfrac a 2 t^2 + v_0 t = 2t^2 + v_0 t\\ s(6)-s(5)=38~m\\ 2(6^2)+6v_0 - 2(5^2)-5v_0 = 38\\ (72-50)+v_0= 38\\ v_0 = 38-22 = 16~m/s\)

If we wanted to use the average speed

\(v(t) = v_0 + at\\ \bar{v}=\dfrac{v(6)+v(5)}{2} = \dfrac{11a+2v_0}{2}= \dfrac{11}{2}a+v_0=22+v_0\\ (22+v_0)~m/s\cdot 1~s = 38~m\\ v_0 = 38-22 = 16~m/s\)

You've asked a zillion of these types of questions now.

Are these for a class?  Are they homework?

What is the reason for posting one after another of these types of problems?

Thank you

Alan is correct as usual.

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\(\text{An earlier similar problem established that the roots are }\\ r = \sqrt{2}+\sqrt{5},~\sqrt{2}-\sqrt{5},~-\sqrt{2}+\sqrt{5},~-\sqrt{2}-\sqrt{5}\\~\\ \text{which results in }\\~\\ p(x) = x^4-14 x^2+9\\ p(1) = 1-14+9 = -4\)

I believe you can thank the writers at Britannica.com for that.

alternatively the expression is trivially factored as

(x+7)(x+1)=0

and you should be able to solve it by inspection from this form.

\(1 \cdot \dfrac 3 4 \dfrac 1 2 \dfrac 1 4 = \dfrac{3}{32}\)

average age of an elephant at a zoo

yes

number of elephants at the San Diego Zoo

no

number of daily visitors at the San Diego Zoo

yes, though I suspect it would be better to model it as one distribution for say september-feb and one for march-aug

(I happen to live in the San Diego area)