whoisjoe

\(\mathrm{Subsititute\:}y=2+\frac{5}{6}\cdot \:x \)

\(\begin{bmatrix}4x-3\left(2+\frac{5}{6}x\right)=3\end{bmatrix}\)

\(\mathrm{Isolate}\:x\:\mathrm{for}\:4x-3\left(2+\frac{5}{6}x\right)=3:\quad x=6\)

\(\mathrm{For\:}y=2+\frac{5}{6}\cdot \:x\)

\(\mathrm{Subsititute\:}x=6\)

\(2+\frac{5}{6}\cdot \:6=7\)

\(y=7, \text{Solution is x=6, y=7}\)

A French term from the Italian basso-relievo ("low relief"), bas-relief (pronounced bah ree. leef) is a sculpture technique in which figures and/or other design elements are just barely more prominent than the (overall flat) background.

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thoughtco.com

according to seasky.org, "Spiral galaxies are characterized by a distinct flattened spiral disk with a bright center called the nucleus. Our own Milky Way is a spiral galaxy." 
It seems that the Milky Way has distinct flattened spiral disk with bright centers. A spiral galaxy is a type of galaxy, and the milky way is the galaxy that contains the solar system.

Hope this helped

You ate 4/5 * 2/3 of the original pizza, which is 8/15. So, you ate 8/15 of the original pizza.

\(\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n\)

\(\left(x^4y^7\right)^{\frac{2}{3}}=\left(x^4\right)^{\frac{2}{3}}\left(y^7\right)^{\frac{2}{3}}\)

\(=\left(x^4\right)^{\frac{2}{3}}\left(y^7\right)^{\frac{2}{3}}\)

Simplify:

=\(x^{\frac{8}{3}}\left(y^7\right)^{\frac{2}{3}}\)

Simplify:

\(x^{\frac{8}{3}}y^{\frac{14}{3}}\)

Final answer:

\(x^{\frac{8}{3}}y^{\frac{14}{3}}\)

More detailed response:

\(\sqrt{72x^5y^4}\)

=\(\sqrt{72}\sqrt{x^5}\sqrt{y^4}\)

=\(6\sqrt{2}\sqrt{x^5}\sqrt{y^4}\)

=\(6\sqrt{2}\sqrt{x^4x^1}\sqrt{y^4}\)

=\(6\sqrt{2}\sqrt{\left(x^2\right)^2}\sqrt{x^1}\sqrt{y^4}\)

=\(6\sqrt{2}x^2\sqrt{x^1}\sqrt{\left(y^2\right)^2}\)

=\(6\sqrt{2}x^2y^2\sqrt{x}\)

=\(6\sqrt{2}x^2y^2\sqrt{x}\)

=\(6x^2y^2\sqrt2x\)

\(6x^2y^2\sqrt2x\)

Simplify the radical by breaking the radicand up into a product of known factors

log(10,000) = 4 = y

rewrite 10,000 in power base form. = 10000 = 10^4

apply the log rule,\( \log _a\left(x^b\right)=b\cdot \log _a\left(x\right)\)

\(\log _{10}\left(10^4\right)=4\log _{10}\left(10\right)\)

so, \(4\log _{10}\left(10\right)\)

apply the other log rule: \(\log _a\left(a\right)=1\)

\(\log _{10}\left(10\right)=1\)

= 1*4

= 4