whoisjoe

Try Drawing a Venn Diagram!

This is just 3 to the 3rd power, or \(3^3\), which is also known as 27.

This is just 3 to the 4th power, or \(3^4\), which is also known as 81.

Whoops! I meant 3^4 power, which is 81.

This is the answer assuming the first case I stated (2 different terms being multiplied)

\(\frac{\left(x^2+x-12\right)\left(3x^2+11x-4\right)}{\left(x-2\right)\left(x^2-4\right)}\)

Are you saying that (x ^ 2 + x - 12)/(x - 2)  is getting multiplied by (3x ^ 2 + 11x - 4)/(x ^ 2 - 4) as 2 seperate terms, like (x ^ 2 + x - 12)/(x - 2) *  (3x ^ 2 + 11x - 4)/(x ^ 2 - 4), or is  (3x ^ 2 + 11x - 4)/(x ^ 2 - 4) in the denominator of (x ^ 2 + x - 12)/(x - 2)? Try using LaTeX to make the problem clearer.

Hmm. We seem to be disagreeing. I think you forgot that y = 2 + 5/6x is a different term than 4x-3y=3, lol. Guest probably should have put something to tell us that they are 2 different terms, unless I am the mistaken one. Oh I see you didn't see that it was a system of equations so you just solved for x!

As for the 5/6x confusion you are having, just put the 5/6x in the term you are substituting in for "y", like I did when I said \(\mathrm{Subsititute\:}y=2+\frac{5}{6}\cdot \:x\)