asinus

Hallo One23Piece,

willkommen bei uns im Forum. Wir freuen uns auf Fragen, die von dir im Forum gestellt werden und erwarten auch Antworten von dir, auf die von anderen gestellten Fragen. Viel Freude bei der Arbeit im Forum

wünscht dir

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Find the area of the triangle.

Hello Guest!

\(Touch\ Point\ P:\\ x_P=8\cdot cos(atan -\frac{1}{2})=7.155\\ y_P=8\cdot sin(atan -\frac{1}{2})=-3.578\\ f(x) =2\cdot (x-x_P)+y_P\\ f(x)=2x-2\cdot 7.155-3.578\\ f(x)=2x-17.888=0\\ P_x\ (8.944,0)\\ P_y(0,-17.888)\)

The area of this triangle is

\(A_{xy}=\frac{1}{2}\cdot 8.944\cdot (-17.888)\)

\(A_{xy}=-79.995\)

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What is the value of x and the length of DE?

Hello Guest!

I understand it like this:

\(f(x)=DE=11x+15\\ g(x)=FG=81\\ 11x+15=81\\ \color{blue}x=6 \)

\(DE=81\)

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\(What\ is\ the\ coeffiicient\ of\ x^2 y^2?\)

Hello Guest!

\((x + y)^4 + (x + 8y)^4=2x^4+36x^3y+390x^2y^2+2052xy^3+4097y^4\)

The coeffiicient of x^2 y^2 is 390.

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Hello Guest!

\(1\ 000\ CSW\cdot \frac{USD}{20\ CSW}=50\ USD\\ 200\ TPA\ Crosswater=200\ USD\)

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what is the value of 60x−2y?

Hello Guest!

\(y=8x+10\\ (x−2)(y−2)=\color{blue}-18\ determined\ graphically\\ x=\frac{\color{blue}-18}{y-2}+2\)

\(x=0,5\\y=14\)

\(60x-2y=60\cdot0,5-2\cdot 14=2\)

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Wie lange wird es noch downloaden?

Hallo Mathefreaker2021!

\((9,54GB-1,2GB)\cdot\frac{10^6KB}{GB}\cdot\frac{s}{135KB}\cdot \frac{h}{3600s}=\color{blue}17,16h=17h\ 9,6s\)

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Find BC.

Hello Guest!

\(f(x)=\sqrt{22^2-x^2}\\ g(x)=\sqrt{13^2-x^2}+13\\ \sqrt{22^2-x^2}=\sqrt{13^2-x^2} +13\\ 22^2-x^2=13^2-x^2+2\cdot 13\cdot \sqrt{13^2-x^2} +13^2\\ 13^2-x^2= (\frac{22^2-13^2-13^2}{26})^2 \\ x=\sqrt{13^2- (\frac{22^2-13^2-13^2}{26})^2}\)

\(x=11.725\\ \overline{BC}=2x\)

\(\overline{BC}=23.449\)

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Find the sum of alldistinct of BC.

Hello Guest!

\(c^2=a^2+b^2-2bc\ cos\ \gamma\\ 4^2=x^2+10^2-2\cdot 10\cdot x\cdot cos\frac{\pi}{6}\\ x^2-20\cdot cos\frac{\pi}{6}\cdot x+100-16\\ x=8.66\pm\sqrt{8.66^2-84}\\ x\in \{\} \)

\(BC\in\{\}\)

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What is a?

Hello Guest!

\(c^2=a^2+b^2-2bc\ cos \alpha\\ 12^2=a^2+10^2-2\cdot a\cdot 10\cdot cos\ 60°\\ a^2-10a-44=0\\ a=5\pm \sqrt{25+44}\\ \color{blue}a=13.31\)

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