I think there are more cases than just -1, 0, 1.
On desmos, the minumn is 10.44, when x = .131.
I'm not too sure how to do it tho. :((
=^._.^=
You're welcome. :))
Hello :))
In Q and R there are 9.
In Q and S there are 4.
In R and S there are 11.
Combined, there are 18 elements, so there are 3 elements that are the same (9+4+11-18)/2.
I find it easier to visualize it through a venn diagram.
Let's just plug this inn.
3A + 2(4) + 5 = 58
3A + 13 = 58
3A = 45
A = 15
Oopsies, my bad. sqrt(30), I must've missed a 0.
And also, it it 6. :)))
Nice job. :DDDD
If there is one value, the discriminant sqrt(b^2 -4ac) = 0.
try solving for that
Try using vietas :))
simplfify 1/(abc) + 1/(abd) + 1/(acd) + 1/(bcd)
Then plug in the numbers from vietas equations
ohh, you have the formula, I'm sure you can do this. :))
s = (sqrt(6) + sqrt(24) + sqrt(3))/2
a = sqrt(6)
b = sqrt(24)
c = sqrt(30)
What's √s(s-a)(s-b)(s-c)
You can plot them into desmos.
Just replace f(x) with y.
x = x/1
The plane is 1.
Can you solve it from there?