6 of 5.98 :))
5.98 * 6
=^._.^=
I think there are actually 2.
You can tell from the discriminant, b^2 - 4ac
If b^2 - 4ac = 0, then there's 1.
If b^2 - 4ac > 0, then there are 2.
If b^2 - 4ac < 0, then there are 0.
If f(0) = 0, c = 0
ax^2 + bx
Since f(1) = 2, a+b = 2.
Since f(2) = 9, 4a + 2b = 9.
a + b = 2
4a + 2b = 9
Can you solve for a and b?
Note that the track is just a split up circle nad rectangle.
For the rectangle part, the outside is 160. (80*2)
For the circle part, the circumfrence is 35pi. (diameter = 35)
So running aorund the track is 160 + 35pi
let's draw a triangle, with the legs, 1 and 2.
So th hypotenues is sqrt(5)
Sine = 2/sqrt(5)
Cos = 1/sqrt(5)
4(x + 7)(2 - x) + (2 - x)
(2-x)(4(x + 7)+1)
(2-x)(4x+29)
Now, it's a quadratic, and we're looking for the vertex.
Can you solve it from here?
I think the soap will be dirty, and the floor will be clean, not too sure tho.
3a - a + a
a(3 - 1 + 1)
a(3)
3a
Yeah, some people are quite mean, but that's not the fault of the app.
It's like blaming gmail for recieving a bad email, it's the fault of the person that sent it, not the app.
On the x axis = (a, 0)
Now we can use the distance formula.
(a-2)^2 + (0-0)^2 = (a-0)^2 + (0-6)^2
a^4 - 4a + 4 = a^2 + 36
-4a = 32
a = -8
I hope that's right. :)
z = a + bi
|z| = a^2 + b^2 = 1
z with line = a - bi
|z| with a line = a^2 + (-b)^2 = 1
So I think the answer is just 1/2.
I'm not sure tho