A/(x - 1) + B/(x + 1) = (A(x+1) + B(x-1))/(x+1)/(x-1) = (2x + 1)/(x^2 - 1)
A(x+1) + B(x-1) = (2x + 1)
(A+B)x + A - B = 2x + 1
A + B = 2
A - B = 1
Can you solve B from here?
=^._.^=
Try using law of sines for this problem.
Sine(A)/a = Sine(B)/b = Sine(C)/c
https://www.khanacademy.org/math/geometry/xff63fac4:hs-geo-non-right-triangles-trigonometry/hs-geo-law-of-sines/v/law-of-sines
x^2 + y^2 = 2x + 2y
x^2 + y^2 - 2x - 2y = 0
(x-1)^2 + (y-1)^2 = 2
x = 2 and y = 2, and x = 0, y = 0 works.
So r = 0+0 and 2+2, but it has to be positive, meaning the answer is 4. :))
Thank you. :))
Here's a hint:
sin(x+y) = sin(x)cos(y) + cos(x)sin(y)
cos^2(x)+sin^2(x) = 1
tan(x) = sin(x)/cos(x)
2l + 2w = 23
(l+2)(w+2) = 58.5
lw + 2(w+l) + 4 = 58.5
lw + 23 + 4 = 58.5
lw = 31.5
The area of the picture is lw. :))
Each ball has 2 options, box 1 of box 2.
5^2 = 25
2/9R = 2(R-40)
2/9R = 2R - 80
80 = 16/9R
R = 45
yayyy :))
C = 2/9R
C = 2(R-40)
Take it from there. :))
Thank you.
I tried it, and it looks amazing. :))