catmg

You're solving for geometric, not arithmetic. 

First, we need to look for the common ratio. 

x, x + y, x + 2y, x + 3y, x + 4y, ...

a_4 = x + 3y

a_16 = x + 15y

Subtract those 2 equations. 

125-41 = x + 15y - (x + 3y)

84 = 12y

y = 7 (that's the common ratio)

a_4 = x + 3y

41 = x + 3(7)

x = 20

So our first term is 20, then we add 7 for the next term. 

a_n = 20 + 7(n-1)

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https://web2.0calc.com/questions/i-am-having-trouble-with-this-question-on-a-semester-review 

See if you can figure it out from this problem. 

We need the starting term (a_1) and we to know how much you increase/decrease from term to term.  

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The numerator of the numbers are 1, 2, 3, 4, 5, ... 100. 

So the numerator should just be i. 

The denominator of the numbers are 4, 6, 8, 10. 

So the denominator should just be 2(i+1). 

There are 100 terms in the sequence, so the top of the sigma has to be 100. 

Put them all together and find the right choice. :))

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Notice that each time, we're adding 9 and that it starts with 12. 

a_n = 12 + 9(n-1)

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Did the latex mess up?

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I assume that Kim finished in 50.9 seconds. 

Since Martin finished the race .267 seconds after, Martin finished in .267 + 50.9. 

How is adding 0.267 to 50.9 different from adding 0.26 to 50.9?

.267 + 50.9 = 51.167

.26 + 50.9 = 51.16

I think the first one is the specific number, but the second is a rounded version. 

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x^2-2x+y^2-10y+20 = x^2-8x+y^2-10y+35

6x = 15

x = 2.5

Now, find the 2 y coordinates to get the 2 coordinates. :))

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Try using the angle bisector theorem. 

8/4.5 = (y-2)/(y/2)

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10C8 = 36

1/2^10*36 is our answer. 

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Done 

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