CPhill

Since  the larger triangle is 16 times that of the smaler, its side is = √16  =  4 times as much

So.....let the side of the smaller  = x

And the side of the larger  is 4x

And we have

3x + 3(4x) = 45

15x = 45

x = 3

So  the sidee of the larger  is  4(3)  = 12

And its area  =   (1/2)(12^2) (√3 / 2)   =  144√3 / 4   =   36√3  in^2

Second one

This is a 30-60-90 right triangle

The  side across from the 30 degree angle  =  (1/2) * hypotenuse  = (1/2) * 6  =   3  =  y

Third one

In a 45-45-90 right triangle,  the hypotenuse is √2  times  either of the legs  =

5√2  =  r

Fourth one :

The side across from the 30 degree angle  =  3

x is across from the 90 degree angle in the second triangle    =  3√2

We only have y intercepts  at  (0, 5)  and (0, -5)

The center is (0,0)

The domain is all reals

The range  is    y ≤  -5     and   y  ≥  5

The third answer is correct

First one:

θ

__

2 pi

θ    r^2

__

 2

x^2  - y^2  =  16   

This is a hyperbola that intersects the x axis in two places and has a center of (0,0)

This hyperbola has two axis of symmetry.....the x axis and the y axis

So.....the last answer is correct

Here's a tool that will order these for you :

https://calculator.tutorvista.com/math/509/least-to-greatest-calculator.html

Here's the graph, NSS :

https://www.desmos.com/calculator/ohp3ma4phc

The thid one is correct

See if you can follow this, RP...it explains it pretty well....step-by-step...it isn't really hard....just a little time-consuming

http://www.purplemath.com/modules/boxwhisk.htm

The first answer

10)

We have  the common ratio  of  1/5

625 (1/5) ^{n - 1}      where n is the nth term

625 (1/5)^10-1

625 (1/5)⁹   =   1  /3125

14)  

First term  =   5(1)  - 4  =  1

Last term  =  5(18) - 4  =  86

Sum  =   [ 1 + 86 ]  (18/2)   =  87 * 9   =  783

14) 

Total  vertical distance    =

  20  [ 1 - (4/5)^(5) ]  / ( 1 - 4/5)  - 10    =  7154 / 125   =   57 + 29/125  ft