Note that angle BAE = angle ECD
And angle ABE = angle EDC
So....by AA congruency, triangle ABE is similar to triangle CDE
And CD : AB = 2: 3
Then the height of CDE = CF is 2/3 height of ABE = FB
So.... CF : FB = 2 : 3
And angle BFE = angle BCD
And angle BEF = angle BDC
So,again, by AA congruency, triangle BDC is similar to triangle BEF
But there are 5 parts of BC....and BF is 3/5 of these
So......BF is 3/5 of BC
So....EF is 3/5 of DC = (3/5) (100) = 60 (cm)