10)The two bases of a right conical frustum have radii 12 and 9. The two bases are 4 units apart. Let the volume of the frustum be V cubic units and the total surface area of the frustum be A square units. Find V + A.
The height = 4
The volume, V, is given by
(1/3) * pi * height ( [radius base 1]^2 + product of the base radii +[ radius base 2]^2 ) =
pi / 3 * 4 * ( 12^2 + 12*9 + 9^2)
pi / 3 * 4 * ( 144 + 108 + 81 )
pi / 3 * 4 * ( 333)
pi * 4 * 111
444 pi
The surface area A, is given by :
pi ( sum of radii) * √ [ (difference of radii)^2 + height^2 ] + pi (radius 1)^2 + pi (radius 2)^2
pi ( 21) √ [ 3^2 + 4^2 ] + pi [ 144 + 81 ]
pi [ 21 * 5 + 225 ]
pi [ 105 + 225 ]
pi [ 330]
330 pi
So
V + A =
[444 +330 ] pi =
774 pi