Let x be the first integer
x + 2 the second
x + 4 the third
x + 6 the fourth
So we have
x + (x + 2) + ( x + 4) + ( x + 6) < 192 simplify
4x + 12 < 192 subtract 12 from both sides
4x < 180 divide both sides by 4
x < 45
So......the greatest even integer < 45 is 44
So...the four consecutive even integers are 44 46 48 and 50
And their sum is 188