CPhill

125 ^ (-4/3)

Note that we can write this as

( 125^1/3)^(-4)        the value in the first parentheses is just the cube root of 125  = 5

So we have

(5)^(-4)          {    remember that  a^(-m)  =   1 / a^m  }

1 / 5^4   =    1 / (5^2 * 5^2)  =   1 / (25 * 25)   =  1 / 625

3(x + 1) (x + 7)  - (2x + 5)^2  simplify

3 (x^2 + 8x + 7) - (2x + 5)(2x + 5)

3x^2 + 24x + 21 - [ 4x^2 + 20x + 25 ]

-x^2 + 4x - 4

The x coordinate of vertex of this function  is given by :

-4/ (2 (-1) )   =  4/2  = 2

And the max value of this function  is  :

-(-2)^2 + 4(2) - 4   =  -4 + 8 - 4  =   0

So....this function is never positive

The base is 3......since this is > 1,  then his represents exponential growth

I don't know....you're always pretty good with these function problems.....!!!

Very nice, hectictar  !!!!

OK....good job  !!!

You should get more than 1 point here, hectictar....!!!

The coefficient is the number in front of the variable  =  -13.1

x^2  - k^2   =  (x + a) (x - b)

(x + k) ( x - k)  =  (x + a) ( x - b)

So   a  =   k     and   b  = k

So

a - b   =  k - k   =    0

47.32 / 3.79   ≈  12.485   gal