CPhill

Here's one more way :

60 mph  = 88 ft/sec

So

15 mph  = 22 ft/ sec

So...in 60 seconds we have    60 * 22  =  1320 ft

See my answer under  your earlier post.....

We can use the  Angle of  Intersecting Chords Theorem

We first need to find the measure  of  minor arc FB....this is given by :

m arc FB  = 360  - 100 - 154 - 40   = 66°

So...the measure of AED  = (1/2) ( m arc FB  + m arc AD)  =  (1/2) ( 66 + 40)  = (1/2)(106)  = 53°

x  = 7 ^ (log ₇ 2  + log ₇ 3)

x = 7^[ log ₇  (2 * 3) ]  

x  = 7^ [ log₇ 6 ]   ......using the log property   a^[log _a b]   = b  , we have 

x  = 6

We can use the Exterior Angle Theorem to  solve this

75  = 28  +  x       subtract 28 from both sides

47°   = x   =  the measure of the other  non-adjacent  interior  angle

log₂ x  + 5 log₂ y  - 3 log ₂ x  =

log₂ x  + log₂ y⁵  - log₂ x³ =

log₂  [ ( x y⁵ ) / x³ ] =

log₂ [ y⁵ / x² ]

ln ( a + b)  + 4 ln ( a - b) - 3 ln c  =

ln (a + b) + ln ( a - b)⁴  - ln c³ =

ln  ( [ (a + b) (a - b)⁴ ] / c³ )

5 log x - 4 log (x² + 1)  + 2 log (x - 1)  =

log x⁵  - log (x² + 1)⁴ + log ( x - 1)²   =

log   [   (x⁵ * (x - 1)² ) / (x² + 1)⁴  ]

Transformation Rule  :  ( 6, -4)

Scale Factor :   3

V_cone   =  pi *( diameter/ 2)^2 * height  / 3   = 3.14 * (1.5 / 2)^2 * 4  = 7.065 in^3

multiplication property of equality

m ∠ F

m ∠ D

substitution property of equality

full

θ / [ 2 pi  ]

A  = θ r^2 / 2