CPhill

Because of the conjugate property, the function will also have the zero  -3 + 2i

So....let the  function be  f(x)  and we have that

f(x)  = a( x + 1)( x - ( - 3 - 2i) ) ( x - (-3 + 2i) )   simplify

f(x)  = a ( x + 1)  ( x^2  -x (-3 + 2i)  -x(-3 -2i)  + ( -3 + 2i) (-3 - 2i) )

f(x)  = a  ( x + 1) ( x^2 + 3x - 2xi + 3x + 2xi + 9 - 4i^2 )

f(x)  = a ( x + 1) (x^2 + 6x + 9 + 4)

f(x)  = a (x + 1)(x^2 + 6x + 13)

f(x)  = a  ( x^3 + 6x^2 + 13x  + x^2 + 6x + 13 )

f(x)  = a  ( x^3 + 7x^2 + 19x + 13)

And  since  f(-9)  = -6, we can find  "a"  as

-6  = a ( (-9)^3 + 7(-9)^2 + 19(-9) + 13)

-6  = a ( -320)

a  =  6 / 320   =  3/160

So.....f(x)  =   (3/160) ( x^3 + 7x^2 + 19x + 13)

∠BDE = ∠BAC

∠BED  = ∠BCA

AA Similarity Postulate

Segment Addition Postulate

HAHAHA!!!!...I wish  !!!!

But...THX anyway....LOL!!!!

We  know an angle and an adjacent side.....and we are  looking for the opposite side

The tangent  function relates all three....so we have...

tan (62°) = x / 40       multiply both sides by 40

40 * tan (62° )   =  x  ≈  75.2 yds

We can use the intersecting chord theorem  that says that

CE * DE  = BE * AE        substituting, we have that

CE * 5 =  3 * 15

CE * 5   = 45        divide both sides by  5

CE  = 45/5  = 9 inches

Here's one thing  to remember....because the sine and  cosine are  co-functions ......

sin (90 - x)°   = cos x°  .....so letting x  =  19°, we have that

sin (90 - 19)°  = cos 19°

sin 71°  = cos 19°

So....x  = 71°

sin C  = h/a

substitution property of equality

associative  property  of  multiplication

Definition of Altitude

sin M  = h/p and sin P = h/m

Multiplication Property of  Equality

psin M     =  m sin P

_____         _________

  pm               pm

If ADB  = 225°, then minor arc AB  = 360  - 225  = 135°

And the measure  of APB  =

(1/2) ( measure of arc ADB  -  measure of  minor arc AB )  =

(1/2) ( 225  - 135)  =

(1/2)(90)  =

45°

f(x)=3x+3

h(x)=e^(2x+1)

i(x)=x^2+4x+3

1.   r(x)=h(i(x)).....here. we are putting the function "i"  into the function "h"  

r(x)  = e^[(2 (x^2 + 4x + 3) + 1]

r(x)  = e^[2x^2 + 8x + 6 + 1]

r(x)  = e^[2x^2 + 8x + 7]

 2.   t(x)=f((h(i(x))).......here we are putting the first result into  "f"

t(x) = 3(e^[2x^2 + 8x + 7 ] ) + 3  =

t(x) = 3 [ e^(2x^2 + 8x + 7)  + 1 ]