Let the middle term = bx
Completing the square on this term would give us
(b / 2)^2 = 4
b^2 / 4 = 4
b^2 = 16 take both roots
b = 4 or b = -4
Since EF ll GH.......then EH = GF
Then
x^2 - 2x = 48 - 4x
x^2 + 2x - 48 = 0
(x + 8) ( x - 6) = 0
The second factor set to 0 ad solved for x gives x = 6
So
EF = (6)^2 - 2(6) = 24° = GH
Then arc EPF = 360 - 2*24 - 70 = 242°
LOL!!!!
Avg speed =
2* product of speeds / sum of speeds =
(2 * 50 * 75) /( 50 + 75) =
7500 / 125 =
60 mph
[ NOT (50 + 75) / 2 = 125 / 2 = 62.5 mph as many think !!! ]
Definitely NOT a square !!!
Easiest way to calculate [ABCD :]
Find the area of rectangle EHFB
From this subtract areas of
Right triangles BEC , CFD , AGD and Trapezoid AGHB
See here, EP :
https://en.wikipedia.org/wiki/Parallelogram_law
Sum = (12)(13) / 2 = 78
Divisible by 1, 2, 3, 6
(I assume that 1 and 10 are inclusive)
f(c) = y
y = -1
The graph only interesects this value once
Not exactly the same problem, but very similar.....
See if this helps :
https://web2.0calc.com/questions/pls-help_94109
Parallelogram Law : The sum of the squares of the four sides of a parallelogram = the sum of the squares of the diagonals
2*7^2 + 2*9^2 = 8^2 + x^2
98 + 162 = 64 + x^2
98 + 162 - 64 = x^2
196 = x^2
sqrt (196) = x = 14 = the longer diagonal
