xy - z = 15
xz - y = 15
yz - x = 15
Subtract the 2nd equation from the 1st
xy - xz + y - z = 0
x (y -z) + 1(y -z) = 0
(x + 1) ( y - z) = 0 since x is positive, divide both sides by (x + 1)
y - z = 0
y = z
Subtract the 3rd equation from the 2nd
xz - yz + x - y = 0
z (x - y) + 1(x - y) = 0
(z + 1) ( x - y) = 0 again, z is positive, divide both sides by (z + 1)
x - y = 0
x = y
So x = y = z
In the 1st equation we have that
x^2 - x = 15
x^2 - x + 1/4 = 15 + 1/4
(x - 1/2)^2 = 61/4
x - 1/2 = sqrt (61) / 2
x = ( 1 + sqrt (61) ) / 2
So
xyz = [ ( 1 + sqrt (61) ) /2 ] ^3 = 23 + 8sqrt (61)
