Here's my best attempt at this one ....
There are C(9,4) = 126 possible sets
If we consider the sets whose product is NOT divisible by 4, we have the folowing cases
Case 1 - the set contains four of the following six integers .... { 1, 2 , 3, 5, 7 , 9 }
Total sets possible = C(6,4) = 15
Case 2 - the set contains four of the following six integers ....{1, 3 , 5, 6, 7 ,9 }
Total sets possible = C(6,4) = 15
Total sets whose product is divisible by 4 = 126 - 2(15) = 96
P ( that the set product is divisible by 4 ) = 96 / 126 = 16 / 21
[ I'd like someone to check this answer.....!!!! ]