80 = (1/2) (12) ( b + b + 4)
80 / 6 = 2b + 4
40/3 = 2b + 4 multiply through by 1/2
20/3 = b + 2
b = 20/3 - 2 = 20/3 - 6/3 = 14/3
b + 4 = 14/3 + 12/3 = 26/3
Assuming that we have an isosceles trapezoid, we can find the length of a side by constructing a right triangle with legs of 12 and [ (b + 4) - b ] / 2 = 2
The side length is sqrt [ 12^2 + 2^2] = sqrt (148) = 2sqrt (37)
The perimeter is 14/3 + 26/3 + 2 * 2sqrt (37) = 40/3 + 4sqrt (37) ≈ 37.66