I used Desmos online graphing calc to aid me.
I know 2 asymtotes are x=-pi and x=pi
I know that secant isthe inverse of cos.
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I am much more familiar with the cos function so I will work out what that muct look like.
It must cross the x axis at -pi and pi That would be half a wavelength. So the wavelength will be 4pi
It has a maximum at y=8 and a minimum at y=-4
So just by thinking, or sctching what I already know. I can say that (0,8) and (2pi,-4) will be the max and min.
** Or they could be (0,-4) and (2pi, 8) but I will wory about that last.
8--4 = 12 the amplitude of the wave is 6, The average of 8 and -4 is 2 so y=2 will be the centre line.
So the cos functions is y=6cos(x/2) + 2 OR y=-6cos(x/2)+2
The sec function will be y=6sec(x/2)+2 or y=-6sec(x/2)+2
OR