Jerry is presently twice as old as his brother and six years older than his sister. How many years from now will Jerry's age be 1/3 of the combined ages of his brother and sister at that time?
Hello Guest!
\(j=2b=s+6\\ j+x=\frac{1}{3}(b+x+s+x)\\ j+x=\frac{1}{3}(\frac{j}{2}+j-6+2x)\\ j+x=\frac{1}{3}\cdot \frac{j+2j-12+4x}{2}\\ 6j+6x=3j-12+4x\)
\(2x=-3j-12\\ -x=\frac{3}{2}j+6\)
- x | 9 12 15 18 21 24 27 30 33 36
j | 2 4 6 8 10 12 14 16 18 20
s | 2 4 6 8 10 12 14
b | 4 5 6 7 8 9 10
At no point was, is and will Jerry be 1/3 the age of his siblings together.
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